Optimal. Leaf size=473 \[ \frac{5 \left (16 c^2 e^2 \left (a^2 e^2-8 a b d e+10 b^2 d^2\right )-8 b^2 c e^3 (4 b d-3 a e)-128 c^3 d^2 e (2 b d-a e)+b^4 e^4+128 c^4 d^4\right ) \tanh ^{-1}\left (\frac{-2 a e+x (2 c d-b e)+b d}{2 \sqrt{a+b x+c x^2} \sqrt{a e^2-b d e+c d^2}}\right )}{16 e^7 \sqrt{a e^2-b d e+c d^2}}-\frac{5 \sqrt{c} (2 c d-b e) \left (-4 c e (2 b d-a e)+b^2 e^2+8 c^2 d^2\right ) \tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{a+b x+c x^2}}\right )}{2 e^7}-\frac{5 \left (a+b x+c x^2\right )^{3/2} \left (-4 c e (3 b d-a e)+b^2 e^2+4 c e x (2 c d-b e)+16 c^2 d^2\right )}{12 e^4 (d+e x)^2}+\frac{5 \sqrt{a+b x+c x^2} \left (2 c e x \left (-4 c e (4 b d-a e)+3 b^2 e^2+16 c^2 d^2\right )-16 c^2 d e (5 b d-2 a e)+12 b c e^2 (2 b d-a e)-b^3 e^3+64 c^3 d^3\right )}{8 e^6 (d+e x)}+\frac{\left (a+b x+c x^2\right )^{5/2} (-b e+4 c d+2 c e x)}{3 e^2 (d+e x)^3} \]
[Out]
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Rubi [A] time = 1.72502, antiderivative size = 473, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 5, integrand size = 28, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.179 \[ \frac{5 \left (16 c^2 e^2 \left (a^2 e^2-8 a b d e+10 b^2 d^2\right )-8 b^2 c e^3 (4 b d-3 a e)-128 c^3 d^2 e (2 b d-a e)+b^4 e^4+128 c^4 d^4\right ) \tanh ^{-1}\left (\frac{-2 a e+x (2 c d-b e)+b d}{2 \sqrt{a+b x+c x^2} \sqrt{a e^2-b d e+c d^2}}\right )}{16 e^7 \sqrt{a e^2-b d e+c d^2}}-\frac{5 \sqrt{c} (2 c d-b e) \left (-4 c e (2 b d-a e)+b^2 e^2+8 c^2 d^2\right ) \tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{a+b x+c x^2}}\right )}{2 e^7}-\frac{5 \left (a+b x+c x^2\right )^{3/2} \left (-4 c e (3 b d-a e)+b^2 e^2+4 c e x (2 c d-b e)+16 c^2 d^2\right )}{12 e^4 (d+e x)^2}+\frac{5 \sqrt{a+b x+c x^2} \left (2 c e x \left (-4 c e (4 b d-a e)+3 b^2 e^2+16 c^2 d^2\right )-16 c^2 d e (5 b d-2 a e)+12 b c e^2 (2 b d-a e)-b^3 e^3+64 c^3 d^3\right )}{8 e^6 (d+e x)}+\frac{\left (a+b x+c x^2\right )^{5/2} (-b e+4 c d+2 c e x)}{3 e^2 (d+e x)^3} \]
Antiderivative was successfully verified.
[In] Int[((b + 2*c*x)*(a + b*x + c*x^2)^(5/2))/(d + e*x)^4,x]
[Out]
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Rubi in Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((2*c*x+b)*(c*x**2+b*x+a)**(5/2)/(e*x+d)**4,x)
[Out]
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Mathematica [A] time = 3.77, size = 562, normalized size = 1.19 \[ \frac{\frac{15 \log (d+e x) \left (16 c^2 e^2 \left (a^2 e^2-8 a b d e+10 b^2 d^2\right )-8 b^2 c e^3 (4 b d-3 a e)-128 c^3 d^2 e (2 b d-a e)+b^4 e^4+128 c^4 d^4\right )}{\sqrt{e (a e-b d)+c d^2}}-\frac{15 \left (16 c^2 e^2 \left (a^2 e^2-8 a b d e+10 b^2 d^2\right )-8 b^2 c e^3 (4 b d-3 a e)-128 c^3 d^2 e (2 b d-a e)+b^4 e^4+128 c^4 d^4\right ) \log \left (2 \sqrt{a+x (b+c x)} \sqrt{a e^2-b d e+c d^2}+2 a e-b d+b e x-2 c d x\right )}{\sqrt{e (a e-b d)+c d^2}}-120 \sqrt{c} (2 c d-b e) \left (4 c e (a e-2 b d)+b^2 e^2+8 c^2 d^2\right ) \log \left (2 \sqrt{c} \sqrt{a+x (b+c x)}+b+2 c x\right )+2 e \sqrt{a+x (b+c x)} \left (\frac{(2 c d-b e) \left (4 c e (41 a e-74 b d)+33 b^2 e^2+296 c^2 d^2\right )}{d+e x}-\frac{2 \left (e (a e-b d)+c d^2\right ) \left (4 c e (3 a e-16 b d)+13 b^2 e^2+64 c^2 d^2\right )}{(d+e x)^2}+8 c \left (2 c e (7 a e-33 b d)+15 b^2 e^2+60 c^2 d^2\right )+\frac{8 (2 c d-b e) \left (e (a e-b d)+c d^2\right )^2}{(d+e x)^3}-32 c^2 e x (3 c d-2 b e)+16 c^3 e^2 x^2\right )}{48 e^7} \]
Antiderivative was successfully verified.
[In] Integrate[((b + 2*c*x)*(a + b*x + c*x^2)^(5/2))/(d + e*x)^4,x]
[Out]
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Maple [B] time = 0.049, size = 28593, normalized size = 60.5 \[ \text{output too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((2*c*x+b)*(c*x^2+b*x+a)^(5/2)/(e*x+d)^4,x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((c*x^2 + b*x + a)^(5/2)*(2*c*x + b)/(e*x + d)^4,x, algorithm="maxima")
[Out]
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((c*x^2 + b*x + a)^(5/2)*(2*c*x + b)/(e*x + d)^4,x, algorithm="fricas")
[Out]
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((2*c*x+b)*(c*x**2+b*x+a)**(5/2)/(e*x+d)**4,x)
[Out]
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GIAC/XCAS [A] time = 17.7955, size = 4, normalized size = 0.01 \[ \mathit{sage}_{0} x \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((c*x^2 + b*x + a)^(5/2)*(2*c*x + b)/(e*x + d)^4,x, algorithm="giac")
[Out]